document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=42247>Question 42247</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve (1/81)^t = 243^t-2.\r<BR>\n" );
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document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #27381 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=27381\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Change everything into powers of 3...so from<BR>\n" );
document.write( "(1/81)^t = 243^(t-2)<BR>\n" );
document.write( "we get<BR>\n" );
document.write( "(3^(-4))^t = (3^5)^(t-2)<BR>\n" );
document.write( "3^(-4t) = 3^(5t-10)<BR>\n" );
document.write( "and thus<BR>\n" );
document.write( "-4t = 5t - 10<BR>\n" );
document.write( "-9t = -10<BR>\n" );
document.write( "t = 10/9 </SPAN>\n" );
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