document.write( "Question 387310: A bag contains 8 red jelly beans and 8 green jelly beans. How many ways can 5 jelly beans be withdrawn from the bag with the number of green ones being less than 3?
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Algebra.Com's Answer #273772 by robertb(5830)![]() ![]() You can put this solution on YOUR website! The 3 possibilities: \n" ); document.write( "3 red, 2 green; \n" ); document.write( "4 red, 1 green; \n" ); document.write( "5 red, 0 green. \n" ); document.write( "The first case: 8C3*8C2 = 56*28 = 1,568. \n" ); document.write( "The secind case: 8C4 * 8C1 = 70*8 = 560. \n" ); document.write( "The third case: 8C5 * 8C0 = 56*1 = 56. \n" ); document.write( "Adding these figures arising from the mutually exclusive cases, we get 1,568 + 560 + 56 = 2,184 ways. \n" ); document.write( " |