document.write( "Question 387310: A bag contains 8 red jelly beans and 8 green jelly beans. How many ways can 5 jelly beans be withdrawn from the bag with the number of green ones being less than 3?
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #273772 by robertb(5830)\"\" \"About 
You can put this solution on YOUR website!
The 3 possibilities:
\n" ); document.write( "3 red, 2 green;
\n" ); document.write( "4 red, 1 green;
\n" ); document.write( "5 red, 0 green.
\n" ); document.write( "The first case: 8C3*8C2 = 56*28 = 1,568.
\n" ); document.write( "The secind case: 8C4 * 8C1 = 70*8 = 560.
\n" ); document.write( "The third case: 8C5 * 8C0 = 56*1 = 56.
\n" ); document.write( "Adding these figures arising from the mutually exclusive cases, we get 1,568 + 560 + 56 = 2,184 ways.
\n" ); document.write( "
\n" );