document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=387271>Question 387271</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If bus A arrives every 27 minutes and bus B arrives every 15 minutes, and both buses arrive at a stop at 5:07am, what time will they arrive at the same time again? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #273753 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=273753\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If bus A arrives every 27 minutes and bus B arrives every 15 minutes, and both buses arrive at a stop at 5:07am, what time will they arrive at the same time again?<BR>\n" );
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document.write( "Find the least common multiple of 15 and 27.<BR>\n" );
document.write( "15 = 3*5<BR>\n" );
document.write( "27 = 3^3<BR>\n" );
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document.write( "lcm = 3^3*5 = 27*5 = 135 minutes<BR>\n" );
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document.write( "5:07 + 135 min = 5:07+ (2hrs 15min) = 7:22 am<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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