document.write( "Question 387271: If bus A arrives every 27 minutes and bus B arrives every 15 minutes, and both buses arrive at a stop at 5:07am, what time will they arrive at the same time again? \n" ); document.write( "
Algebra.Com's Answer #273751 by edjones(8007)![]() ![]() You can put this solution on YOUR website! 27*15=405 \n" ); document.write( "405/3=135 they are both (27 and 15) divisible by 3. \n" ); document.write( "135/27=5 \n" ); document.write( "135/15=9 \n" ); document.write( ". \n" ); document.write( "135/60=9/4=1:45 \n" ); document.write( "5:07 + 1:45 = 6:52 AM The next time that they will arrive together. \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " |