document.write( "Question 387261: Is the relationship below linear? Tell how you decided. Write an equation for the linear relationship.
\n" ); document.write( "x 5 10 15 20 25 30
\n" ); document.write( "y 20 30 40 50 50 50\r
\n" ); document.write( "\n" ); document.write( "I am completely lost. I tried understanding what my chapter was saying but it is only confusing me more.\r
\n" ); document.write( "\n" ); document.write( "Am I even on the right track?
\n" ); document.write( "x/y 5/20 10/30 15/40 20/50 25/50 30/50
\n" ); document.write( "x/y .25 .333 .375 .4 .5 .6
\n" ); document.write( "

Algebra.Com's Answer #273738 by robertb(5830)\"\" \"About 
You can put this solution on YOUR website!
If we use the first pair of data to get the slope of the line passing through them, then we would get \"m+=+%2830-20%29%2F%2810-5%29+=+10%2F5+=+2\". If we use the first pair of x,y data, the point-slope form of the line would be y - 20= = 2(x-5), or y = 2x + 10, after simplifying. Our linear equation would describe the first 4 pairs of data, but not the 5th and the 6th pairs. Therefore the relationship is NOT linear. \n" ); document.write( "
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