document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=386744>Question 386744</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Sovling inequalities:  2^(3n-1)>=(1/8)^n </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #273737 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=273737\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%5E%283n-1%29%3E=%281%2F8%29%5En ALIGN=MIDDLE  ALT=\"2%5E%283n-1%29%3E=%281%2F8%29%5En\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  This inequality is the same as <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%5E%283n-1%29%3E=2%5E%28-3n%29 ALIGN=MIDDLE  ALT=\"2%5E%283n-1%29%3E=2%5E%28-3n%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Now take the base-2 logarithm of both sides of the inequality, to get <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3n+-+1+%3E=+-3n ALIGN=MIDDLE  ALT=\"3n+-+1+%3E=+-3n\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  This inequality is true because we know the base-2 logarithm function is an INCREASING function.  Hence, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6n+%3E=+1 ALIGN=MIDDLE  ALT=\"6n+%3E=+1\"   DISABLED_style= \"max-width:90%; height:auto;\" >, or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=n+%3E=+1%2F6 ALIGN=MIDDLE  ALT=\"n+%3E=+1%2F6\"   DISABLED_style= \"max-width:90%; height:auto;\" >. </SPAN>\n" );
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