document.write( "Question 387180: Please help me solve this equation:\r
\n" ); document.write( "\n" ); document.write( "If 2x + 2y = 10 and y = x + 1, what is the value of x?\r
\n" ); document.write( "\n" ); document.write( "Thanks! \n" ); document.write( "
Algebra.Com's Answer #273680 by gwendolyn(128)\"\" \"About 
You can put this solution on YOUR website!
First, we can substitute the value of y into the first equation.
\n" ); document.write( "2x+2y=10
\n" ); document.write( "2x+2(x+1)=10
\n" ); document.write( "Then, we distribute the two in the equation's first half.
\n" ); document.write( "2x+2(x+1)=10
\n" ); document.write( "2x+2x+2=10
\n" ); document.write( "Then, we combine the two \"2x\"s
\n" ); document.write( "4x+2=10
\n" ); document.write( "Next, we subtract 2 from both sides.
\n" ); document.write( "4x+2=10
\n" ); document.write( "4x+2-2=10-2
\n" ); document.write( "4x=8
\n" ); document.write( "Finally, we divide both sides by four to isolate the variable.
\n" ); document.write( "4x=8
\n" ); document.write( "\"4x%2F4=8%2F4\"
\n" ); document.write( "x=2\r
\n" ); document.write( "\n" ); document.write( "To check:
\n" ); document.write( "y=x+1
\n" ); document.write( "y=4+1
\n" ); document.write( "y=5
\n" ); document.write( "2x+2y=10
\n" ); document.write( "\"2%2A2%2B2%2A3\"=10
\n" ); document.write( "4+6=10
\n" ); document.write( "10=10
\n" ); document.write( "This is correct, so x is equal to 2.
\n" ); document.write( " \n" ); document.write( "
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