document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=387109>Question 387109</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the factored form of 4k^3-13k^2-12k </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #273634 by </B><A HREF=/tutors/aboutme.mpl?userid=tara0066><B>tara0066(31)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tara0066><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tara0066><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=273634\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> k(4k^2-13k-12)   Pull out what they have in common, in this case a k<BR>\n" );
document.write( "Multiply your first value (4) and last value (-12). Find a number that multiplies to get -48 and their sum comes to -13 (which is your middle term). <BR>\n" );
document.write( "3(-16) works for both situations.\r<BR>\n" );
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document.write( "k[4k^2-16k+3k-12]  Replaced middle term with the values you found. Order doesn't matter.<BR>\n" );
document.write( "k[4k(k-4)+3(k-4)] Split the 4 terms into two sets and pull out what the pairs have in common. Your two parenthesis inside should always match if you did this right.\r<BR>\n" );
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document.write( "k(k-4)(4k+3)   Write the repeated set once and the other set comes from the values that you factored out. Don't forget the k from the beginning that was pulled out. It is still out there.\r<BR>\n" );
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document.write( "Hard to follow this one. A little complicated. Hope you could stay with me. lol. Good luck. </SPAN>\n" );
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