document.write( "Question 387077: how do i solve this quadratic function so i can then graph it? y=(x+3) (x-2) \n" ); document.write( "
Algebra.Com's Answer #273628 by tara0066(31)\"\" \"About 
You can put this solution on YOUR website!
Well, this formula is the x-intercept formula (also known as roots). You can put each set equal to zero to solve for the x-intercepts.
\n" ); document.write( "x+3=0 Subtract your 3 over
\n" ); document.write( "x=-3\r
\n" ); document.write( "\n" ); document.write( "x-2=0 Add your 2 over
\n" ); document.write( "x=2\r
\n" ); document.write( "\n" ); document.write( "These are your roots, where your parabola is going to hit on the x-axis.
\n" ); document.write( "To get the vertex, you take the average of these two numbers. That will give you your x value for your vertex.\r
\n" ); document.write( "\n" ); document.write( "2+(-3)=-1/2 x=-1/2 You add the two values and divide by two.
\n" ); document.write( "y=(-1/2+3)(-1/2-2) Plug in the value for x and solve for y. This will give you the y value of vertex
\n" ); document.write( "y=(5/2)(-5/2)
\n" ); document.write( "y=-25/4 or -6 1/4\r
\n" ); document.write( "\n" ); document.write( "So vertex is at (-1/2, -6 1/4) This parabola is opening up because there is no negative out front of parenthesis, and it will cross the x-axis at 2 and -3. This should be enough information to graph this parabola. \n" ); document.write( "
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