document.write( "Question 387068: this is a tough one!
\n" ); document.write( "In 1994 the life expectancy of males in a certain country was 63.5 years. In 1999, it was 66.9 years. Let E represent the life expectancy in year t and let t represent the number of years since 1994.
\n" ); document.write( "The linear fuction E(t) that fits the data is
\n" ); document.write( "E(t)=_t+_ (round to the nearest)\r
\n" ); document.write( "\n" ); document.write( "Use the function to predict the life expectancy of males in 2008.
\n" ); document.write( "E(14)=_
\n" ); document.write( "(round to the nearest)
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Algebra.Com's Answer #273615 by richard1234(7193)\"\" \"About 
You can put this solution on YOUR website!
The \"slope\" is (66.9 - 63.5)/5 = .68, and E(0) = 63.5. Therefore the function should be E(t) = 63.5 + .68t.\r
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\n" ); document.write( "\n" ); document.write( "E(14) = 63.5 + .68(14) = 73.02 years
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