document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=5386>Question 5386</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the perimeter of a rectangular house is 25 1/3 yards, and the length is 22 feet. What is the width?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #2736 by </B><A HREF=/tutors/aboutme.mpl?userid=Abbey><B>Abbey(339)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Abbey><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=2736\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
document.write( "\n" );
document.write( "Convert the total perimeter to feet, by multiplying 25 by 3 (3 feet in a yard) and adding one (to account for the 1/3) = 76 feet\r<BR>\n" );
document.write( "\n" );
document.write( "perimeter = 2L + 2W<BR>\n" );
document.write( "76=2(22)+2W<BR>\n" );
document.write( "76=44+2w<BR>\n" );
document.write( "76-44=2W<BR>\n" );
document.write( "32=2w<BR>\n" );
document.write( "16=w\r<BR>\n" );
document.write( "\n" );
document.write( "The width is equal to 16 feet\r<BR>\n" );
document.write( "\n" );
document.write( "Check your answer:<BR>\n" );
document.write( "2*16=32<BR>\n" );
document.write( "2*22=44<BR>\n" );
document.write( "32+44=76 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );