document.write( "Question 387079: solve for x:\r
\n" ); document.write( "\n" ); document.write( "log x + log(x-1) = log(4x)
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Algebra.Com's Answer #273597 by nerdybill(7384)\"\" \"About 
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log x + log(x-1) = log(4x)
\n" ); document.write( "log x(x-1) = log(4x)
\n" ); document.write( "x(x-1) = (4x)
\n" ); document.write( "x^2-x = 4x
\n" ); document.write( "x^2-5x = 0
\n" ); document.write( "x(x-5) = 0
\n" ); document.write( "x = {0,5}
\n" ); document.write( "Testing for \"extraneous solutions\" we must toss out 0 leaving:
\n" ); document.write( "x = 5\r
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