document.write( "Question 387045: a train an a car leave at the same time 8:00 am on a 156 mile trip the train travels at 80 mph with a 30 minute layover the car travels at 55 mph which will arrive first.\" please show equation \" \n" ); document.write( "
Algebra.Com's Answer #273591 by CharlesG2(834)\"\" \"About 
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\"a train an a car leave at the same time 8:00 am on a 156 mile trip the train travels at 80 mph with a 30 minute layover the car travels at 55 mph which will arrive first.\" please show equation \"\"\r
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\n" ); document.write( "\n" ); document.write( "Distance = Rate * Time
\n" ); document.write( "Car's Distance = Train's Distance = 156 miles
\n" ); document.write( "Car's Rate = 55 mph = CR
\n" ); document.write( "Train's Rate = 80 mph = TR
\n" ); document.write( "30 minutes = 0.5 hours
\n" ); document.write( "Car's Time --> 156 miles / 55 mph = 2.8363 (63 repeating) hours
\n" ); document.write( "156 - (55 * 2) = 156 - 110 = 46 --> 46/55 of 60 minutes -->
\n" ); document.write( "50.1818 (18 repeating) minutes --> car takes 2 hours and 50 minutes -->
\n" ); document.write( "so car arrives 10:50 AM
\n" ); document.write( "Train's Time Nonstop --> 156 miles / 80 mph = TTN = 1.95
\n" ); document.write( "Train's Time = TT = 1.95 + 0.5 = 2.45 hours -->
\n" ); document.write( "0.45 * 60 minutes = 27 minutes -->
\n" ); document.write( "train takes 2 hours and 27 minutes --> train arrives at 10:27 AM\r
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\n" ); document.write( "\n" ); document.write( "train arrives first \n" ); document.write( "
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