document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=387018>Question 387018</A>: <I><SPAN STYLE=\"word-break: break-all;\"> During a kayaking trip, a kayaker travels 12 miles upstream (against the current) and 12 miles downstream (with the current).  The speed of the current remained constant during the trip.  It took 3 hours going upstream and 2 hours going downstream.  Find the average speed of the kayak in still water and the speed of the current.\r<BR>\n" );
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document.write( "I have tried solving the upstream and the downsteam, separately, using D=RT that I found in a tutor's solution to a similar question.  I keep getting the current speed is 0.  Can you help me? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #273582 by </B><A HREF=/tutors/aboutme.mpl?userid=CharlesG2><B>CharlesG2(834)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CharlesG2><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=273582\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \"During a kayaking trip, a kayaker travels 12 miles upstream (against the current) and 12 miles downstream (with the current).  The speed of the current remained constant during the trip.  It took 3 hours going upstream and 2 hours going downstream.  Find the average speed of the kayak in still water and the speed of the current.\r<BR>\n" );
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document.write( "I have tried solving the upstream and the downsteam, separately, using D=RT that I found in a tutor's solution to a similar question.  I keep getting the current speed is 0.  Can you help me?\"\r<BR>\n" );
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document.write( "Distance = Rate * Time<BR>\n" );
document.write( "upstream current will slow speed, downstream current will increase speed<BR>\n" );
document.write( "let KU = kayak rate upstream, KD = kayak rate downstream<BR>\n" );
document.write( "upstream: 12 miles = KU * 3 hours<BR>\n" );
document.write( "12/3 = 4 mph = KU<BR>\n" );
document.write( "downstream: 12 miles = KD * 2 hours<BR>\n" );
document.write( "12/2 = 6 mph = KD<BR>\n" );
document.write( "rate upstream is 4 mph, rate downstream is 6 mph<BR>\n" );
document.write( "so rate in still water must be 5 mph since subtracting or adding same number from the rate in still water<BR>\n" );
document.write( "then current speed is 1 mph<BR>\n" );
document.write( "upstream: 5 mph - 1 mph = 4 mph<BR>\n" );
document.write( "downstream 5 mph + 1 mph = 6 mph<BR>\n" );
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