document.write( "Question 386973: the perimeter of a rectangular cow pasture is 12,000 yards. the length is 50 yards less than 4 times the width. what are the dimensions of the pastures? \n" ); document.write( "

Algebra.Com's Answer #273513 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,         
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document.write( "Let x and (4x-50) represent the width and the length respectively
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document.write( "Question states***
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document.write( "12,000 = x + x + (4x-50) + (4x - 50)
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document.write( "solving for x
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document.write( " 12,000 = 10x - 100
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document.write( "  12,100 = 10x
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document.write( "   1210 = x, the width.  the lenth is 4790    (4*1210 -50)\r
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document.write( "CHECKING our Anwer
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document.write( " 2*1210 + 2*4790 = 2420 + 9580 = 12,000 \n" );
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