document.write( "Question 386971: Hi, Can someone please help me with this. Thanks\r
\n" ); document.write( "\n" ); document.write( "y = + square root (2x-3) \r
\n" ); document.write( "\n" ); document.write( "Explain the why this is a function\r
\n" ); document.write( "\n" ); document.write( "State the domain and range
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Algebra.Com's Answer #273489 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
y = + square root (2x-3)
\n" ); document.write( "Explain the why this is a function
\n" ); document.write( "State the domain and range
\n" ); document.write( "-------------------------
\n" ); document.write( "That \"plus\" sign in front of the square root says
\n" ); document.write( "you are only going to have one y-value for each
\n" ); document.write( "value of sqrt(2x-3). That makes it a function.
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\n" ); document.write( "Domain:
\n" ); document.write( "2x-3 must be non-negative.
\n" ); document.write( "Solve 2x-3>=0
\n" ); document.write( "x >= 3/2
\n" ); document.write( "Domain: All Real Numbers >= 3/2
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\n" ); document.write( "Range:
\n" ); document.write( "Since y is never negative,
\n" ); document.write( "Range: All Real Numbers >= 0
\n" ); document.write( "==========
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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