document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=386919>Question 386919</A>: <I><SPAN STYLE=\"word-break: break-all;\"> At 9:00 a.m. a truck leaves the truck yard and travels west at a rate of 35 mi/hr two hours later a second truck leaves the same route traveling at 70 mi/hr When will the second truck catch up to the first </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #273479 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=273479\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> At 9:00 a.m. a truck leaves the truck yard and travels west at a rate of 35 mi/hr two hours later a second truck leaves the same route traveling at 70 mi/hr When will the second truck catch up to the first<BR>\n" );
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document.write( "Truck A 9.00 AM speed = 35 mph<BR>\n" );
document.write( "Truck B 11.00 AM speed = 70mph<BR>\n" );
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document.write( "when Truck B starts Truck A in 2 hours has traveled = 35*2 = 70 miles<BR>\n" );
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document.write( "Both are travelling in same direction.<BR>\n" );
document.write( "catch up speed = 70-35 = 35 mph<BR>\n" );
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document.write( "catch up distance / catch up speed = time<BR>\n" );
document.write( "70/35 = 2hours<BR>\n" );
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document.write( "Truck B will catch up at 11.00 AM<BR>\n" );
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document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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