document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=386706>Question 386706</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the following  equation. assume that all angles are acute \r<BR>\n" );
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document.write( "Sin(3B-20`)= Cos(5B+30`)\r<BR>\n" );
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document.write( "` is my degree sign because i cant figure out how to get one </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #273438 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=273438\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sin(3B - 20) = cos(5B + 30) = sin(90-(5B+30)) = sin(60-5B).<BR>\n" );
document.write( "Then either 3B - 20 = 60- 5B, <BR>\n" );
document.write( "or 3B - 20 = 180 - (60 - 5B).<BR>\n" );
document.write( "The first equation gives 8B = 80, or B = 10. (A POSITIVE acute angle.)<BR>\n" );
document.write( "The second equation gives 3B - 20 = 120 + 5B, or B = -70.  (A NEGATIVE acute angle.)<BR>\n" );
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