document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=386846>Question 386846</A>: <I><SPAN STYLE=\"word-break: break-all;\"> x-(-3)=-5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #273425 by </B><A HREF=/tutors/aboutme.mpl?userid=zf><B>zf(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=zf><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=273425\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X-(-3)=-5\r<BR>\n" );
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document.write( "You must first start by getting X by itself. In order to do this, you must subtract -3. \r<BR>\n" );
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document.write( "X+3=-5 Whenever I solve a problem with subtracting a negative, I change my signs, because whenever you subtract a negative, you're really adding. \r<BR>\n" );
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document.write( "X+3-3=-5-3 You now must isolate the X. You start by subtracting 3 from each side.\r<BR>\n" );
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document.write( "X=-5-3 The 3's with the X are now gone, and you just do basic math now.\r<BR>\n" );
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document.write( "X=-8 </SPAN>\n" );
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