document.write( "Question 386732: If the area of a rectangle is 50 inches and lenght is two times the width, what is the lenght and width? \n" ); document.write( "

Algebra.Com's Answer #273399 by rapaljer(4671) $\"\"$ $\"About$

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Let x= width
\n" ); document.write( "2x= length\r
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\n" ); document.write( "\n" ); document.write( "Area = W*L
\n" ); document.write( "Area = x*2x=50 Square Inches\r
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\n" ); document.write( "\n" ); document.write( "2x^2=50\r
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\n" ); document.write( "\n" ); document.write( "Divide both sides by 2:
\n" ); document.write( "x^2=25\r
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\n" ); document.write( "\n" ); document.write( "There are two solutions: x=5 and x=-5. However, you have to reject any negative values, since you can't have a negative width.\r
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\n" ); document.write( "\n" ); document.write( "x=5 inches = WIDTH
\n" ); document.write( "2x=2*5 = 10 inches = LENGTH\r
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\n" ); document.write( "\n" ); document.write( "Check: Area = W*L=5*10= 50 square inches.\r
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