document.write( "Question 42175: problem 24 in our self practice i need help\r
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\n" ); document.write( "\n" ); document.write( "complete the ordered pairs so that each is a solution for the given equation \r
\n" ); document.write( "\n" ); document.write( "3x +4y =12 (0, ) , ( ,3 over 4) , ( ,0) , (8 over 3, )
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Algebra.Com's Answer #27339 by psbhowmick(878)\"\" \"About 
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\"3x+%2B4y+=12\"
\n" ); document.write( "or \"4y=12-3x\"
\n" ); document.write( "or \"y=%2812-3x%29%2F4\"
\n" ); document.write( "or \"y=3-3x%2F4\" ________(1)\r
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\n" ); document.write( "\n" ); document.write( "\"3x+%2B4y+=12\"
\n" ); document.write( "or \"3x=12-4y\"
\n" ); document.write( "or \"x=%2812-4y%29%2F3\"
\n" ); document.write( "or \"x=4-4y%2F3\" _________(2)\r
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\n" ); document.write( "\n" ); document.write( "From (1)
\n" ); document.write( "When x = 0, \"y+=+3+-3%2A0%2F4=3\"
\n" ); document.write( "When \"x=8%2F3\", \"y+=+3+-3%2A%288%2F3%29%2F4=1\"\r
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\n" ); document.write( "\n" ); document.write( "From (2)
\n" ); document.write( "When y=0, \"x=4-4%2A0%2F3\"
\n" ); document.write( "When \"y=3%2F4\", \"x=4-4%2A%283%2F4%29%2F3=3\"
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\n" ); document.write( "\n" ); document.write( "Hence, the ordered pairs are:
\n" ); document.write( "(0,3) ; (3,\"3%2F4\") ; (4,0) ; (\"8%2F3\",1)
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