document.write( "Question 386787: how do you solve this? please give step by step instructions. logx(2x-3)=1 \n" ); document.write( "
Algebra.Com's Answer #273378 by stanbon(75887)\"\" \"About 
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logx(2x-3)=1
\n" ); document.write( "---
\n" ); document.write( "base = x
\n" ); document.write( "exponent = 1
\n" ); document.write( "result = 2x-3
\n" ); document.write( "----
\n" ); document.write( "Write in exponential form:
\n" ); document.write( "x^1 = (2x-3)
\n" ); document.write( "x = 2x-3
\n" ); document.write( "x = 3
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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