document.write( "Question 386758: Mona's age is 4 times Bailey's age. The sum of their ages is 15. Find the age of each. \n" ); document.write( "
Algebra.Com's Answer #273353 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Mona's age is 4 times Bailey's age. \n" ); document.write( "The sum of their ages is 15. \n" ); document.write( "Find the age of each. \n" ); document.write( "--------------------- \n" ); document.write( "Equations: \n" ); document.write( "m = 4b \n" ); document.write( "m+b = 15 \n" ); document.write( "---- \n" ); document.write( "Substitute for \"m\" and solve for \"b\": \n" ); document.write( "4b + b = 15 \n" ); document.write( "5b = 15 \n" ); document.write( "b = 3 (Bailey's age now) \n" ); document.write( "--- \n" ); document.write( "Since m = 3b, m = 3*3 = 9 (Mona's age now) \n" ); document.write( "=========================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |