document.write( "Question 386758: Mona's age is 4 times Bailey's age. The sum of their ages is 15. Find the age of each. \n" ); document.write( "
Algebra.Com's Answer #273353 by stanbon(75887)\"\" \"About 
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Mona's age is 4 times Bailey's age.
\n" ); document.write( "The sum of their ages is 15.
\n" ); document.write( "Find the age of each.
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\n" ); document.write( "Equations:
\n" ); document.write( "m = 4b
\n" ); document.write( "m+b = 15
\n" ); document.write( "----
\n" ); document.write( "Substitute for \"m\" and solve for \"b\":
\n" ); document.write( "4b + b = 15
\n" ); document.write( "5b = 15
\n" ); document.write( "b = 3 (Bailey's age now)
\n" ); document.write( "---
\n" ); document.write( "Since m = 3b, m = 3*3 = 9 (Mona's age now)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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