document.write( "Question 42189: 1/12, 2/13, 3/14, 4/15...
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Algebra.Com's Answer #27332 by psbhowmick(878)\"\" \"About 
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Let us denote the first term by 't1', second term by 't2' and so on.\r
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\n" ); document.write( "\n" ); document.write( "\"t2%2Ft1=%282%2F13%29%2F%281%2F12%29=24%2F13\"\r
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\n" ); document.write( "\n" ); document.write( "\"t3%2Ft2=%283%2F14%29%2F%282%2F13%29=39%2F28\"\r
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\n" ); document.write( "\n" ); document.write( "\"t4%2Ft3=%284%2F15%29%2F%283%2F14%29=56%2F45\"\r
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\n" ); document.write( "\n" ); document.write( "So, clearly, the numbers are not in G.P. or Geometric Progression as there is no common ratio.\r
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\n" ); document.write( "\n" ); document.write( "Again,
\n" ); document.write( "\"t2-t1=2%2F13-1%2F12=11%2F156\"\r
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\n" ); document.write( "\n" ); document.write( "\"t3-t2=3%2F14-2%2F13=11%2F182\"\r
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\n" ); document.write( "\n" ); document.write( "\"t4-t3=4%2F15-3%2F14=11%2F210\"\r
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\n" ); document.write( "\n" ); document.write( "So, clearly, the numbers are not in A.P. or Arithmetic Progression as there is no common difference.\r
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\n" ); document.write( "\n" ); document.write( "Hence the numbers are neither in A.P. nor in G.P.
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