document.write( "Question 42202: Given that the sum of the interior angles of a regular polygon is four times \r
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\n" ); document.write( "\n" ); document.write( "the sum of its exterior angles.\r
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\n" ); document.write( "\n" ); document.write( "Find the number of sides of this regular polygon.
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Algebra.Com's Answer #27327 by psbhowmick(878)\"\" \"About 
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Let each interior angle of the regular polygon = \"x%5Eo\".
\n" ); document.write( "Then, each exterior angle = \"%28180-x%29%5Eo\".\r
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\n" ); document.write( "\n" ); document.write( "Let the no. of sides = n.
\n" ); document.write( "Then sum of all interior angles = \"nx%5Eo\" and that of all exterior angles = \"n%28180-x%29%5Eo\".\r
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\n" ); document.write( "\n" ); document.write( "Given: sum of all interior angles = 4 x (sum of all exteriors)
\n" ); document.write( "So, \"nx+=+4n%28180-x%29\"
\n" ); document.write( "or \"x+=+4%2A180+-+4x\"
\n" ); document.write( "or \"5x+=+720\"
\n" ); document.write( "or \"x+=+720%2F5\" = 144\r
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\n" ); document.write( "\n" ); document.write( "Thus each interior angle = \"144%5Eo\" and each exterior angle = \"%28180-144%29%5Eo+=+36%5Eo\".\r
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\n" ); document.write( "\n" ); document.write( "We know that the sum of all the exterior angles of a regular polygon is \"360%5Eo\".\r
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\n" ); document.write( "\n" ); document.write( "Therefore, \"n%2A36=360\"
\n" ); document.write( "or \"n=360%2F36\"
\n" ); document.write( "or n = 10\r
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\n" ); document.write( "\n" ); document.write( "So the reqd. no. of sides of the regular polygon is 10.
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