document.write( "Question 386512: Find the ratio at which 50% alcohol be mixed with 75% alcohol to form a
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Algebra.Com's Answer #273253 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "using the example of forming a 100L solution         
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document.write( "Let x and (100-x)represent the amount of the 75% and 50% solutions respectively
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document.write( "Mixing to the form 100L of the 60% solution 
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document.write( " .75x + .50(100L-x) = .60*100L
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document.write( "            .25x = .10*100L
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document.write( "               x = 10L/.25 = 40L, the 75%,   60L, the 50%
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document.write( " Ratio of the 50% alcohol be mixed with 75% alcohol
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document.write( "                   60/40 = 6/4 = 3/2 OR 3:2      \n" );
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