document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=42157>Question 42157</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangular brick wall is 68 feet and its area is 280 square feet.  What is the length of the longer side of the wall? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #27318 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=27318\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Here <BR>\n" );
document.write( "P = 2L + 2W = 68<BR>\n" );
document.write( "A = LW = 280<BR>\n" );
document.write( "Now divide by two...and get<BR>\n" );
document.write( "L + W = 34<BR>\n" );
document.write( "W = 34 - L<BR>\n" );
document.write( "now substitute<BR>\n" );
document.write( "A = LW = L(34 - L) = 280<BR>\n" );
document.write( "34L - L^2 = 280<BR>\n" );
document.write( "L^2 - 34L + 280 = 0<BR>\n" );
document.write( "(L - 14)(L - 20) = 0<BR>\n" );
document.write( "L = 14 or L = 20<BR>\n" );
document.write( "Thus L = 20 and W = 14 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );