document.write( "Question 386427: Last year, Evelina invested $10,000.00, part at 6% annual interest and part at 8% annual interest. If she received $760.00 in interest at the end of the year, how much did she invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #273170 by rfer(16322)![]() ![]() ![]() You can put this solution on YOUR website! 0.06x+0.08(10000-x)=760 \n" ); document.write( "0.06x+800-0.08x=760 \n" ); document.write( "-0.02x=-40 \n" ); document.write( "x=2000 at 6% \n" ); document.write( "10000-x=8000 at 8% \n" ); document.write( " |