document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=386369>Question 386369</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two terms of an arithmetic sequence are a9 = 85 and a30 = 295. Find a rule for the nth term. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #273151 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=273151\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the 21 differences between a9 and a30 equals 210 (295-85)<BR>\n" );
document.write( "so the difference between consecutive terms is 10 (210/21)\r<BR>\n" );
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document.write( "an = nd + a0 ___ a9 = 9(10) + a0 ___ 85 = 90 + a0 ___ -5 = a0\r<BR>\n" );
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document.write( "an = n(10) - 5 </SPAN>\n" );
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