document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=386284>Question 386284</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The hypotenuse of a right triangle is 1 cm longer than the longer leg. The shorter leg is 7 cm shorter than the longer leg. Find the length of the longer leg of the triangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #273096 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=273096\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The hypotenuse of a right triangle is 1 cm longer than the longer leg. The shorter leg is 7 cm shorter than the longer leg. Find the length of the longer leg of the triangle.<BR>\n" );
document.write( "...<BR>\n" );
document.write( "longer leg =x<BR>\n" );
document.write( "shorter leg = x-7<BR>\n" );
document.write( "hypotenuse=x+1<BR>\n" );
document.write( "...<BR>\n" );
document.write( "(x+1)^2=(x-7)^2+x^2<BR>\n" );
document.write( "x^2+2x+1=x^2-14x+49+x^2<BR>\n" );
document.write( "re organize the terms<BR>\n" );
document.write( "x^2-14x-2x+49-1=0<BR>\n" );
document.write( "x^2-16x+48=0<BR>\n" );
document.write( "x^2-12x-4x+48=0<BR>\n" );
document.write( "x(x-12)-4(x-12)=0<BR>\n" );
document.write( "(x-12)(x-4)=0<BR>\n" );
document.write( "...<BR>\n" );
document.write( "longer leg = 12<BR>\n" );
document.write( "shorter leg = 5<BR>\n" );
document.write( "hypotenuse= 13<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );