document.write( "Question 386273: A stack of $20, $50, and $100 bills were retrieved as part of a police investigation. There were 49 more $50 bills than $100 bills. Also, the number of $20 bills were 3 times the number of $100 bills. If the total value of the money was $6650, find the number of each type of bill. \n" ); document.write( "
Algebra.Com's Answer #273088 by mananth(16946)\"\" \"About 
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A stack of $20, $50, and $100 bills were retrieved as part of a police investigation. There were 49 more $50 bills than $100 bills. Also, the number of $20 bills were 3 times the number of $100 bills. If the total value of the money was $6650, find the number of each type of bill.
\n" ); document.write( "..
\n" ); document.write( "$100 bill = x
\n" ); document.write( "$50 bill = x+49
\n" ); document.write( "$20 bill = 3x
\n" ); document.write( "..
\n" ); document.write( "total = $6650
\n" ); document.write( "..
\n" ); document.write( "100x+50(x+49)+20*3x=6650
\n" ); document.write( "...
\n" ); document.write( "100x+50x+2450+60x=6650
\n" ); document.write( "210x+2450=6650
\n" ); document.write( "210x=6650-2450
\n" ); document.write( "210x=4200
\n" ); document.write( "/210
\n" ); document.write( "x=20
\n" ); document.write( "....
\n" ); document.write( "$100 bill = x = 20
\n" ); document.write( "$50 bill = x+49=69
\n" ); document.write( "$20 bill = 3x=60
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( " \n" ); document.write( "
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