document.write( "Question 386243: A 400 gram solution is 25% salt. How much salt must be added to produce a solution that is 40% salt? \n" ); document.write( "
Algebra.Com's Answer #273087 by gwendolyn(128)\"\" \"About 
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First of all, we'll determine our variables:
\n" ); document.write( "let x=grams of salt that you already have
\n" ); document.write( "let y=grams of salt that need to be added
\n" ); document.write( "let z=total amount of salt in the solution after adding salt\r
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\n" ); document.write( "\n" ); document.write( "We know that salt makes up 25% of the 400g solution, and that 25% can also be written as .25. Thus, we can write an equation to determine x's value:
\n" ); document.write( "x=.25*400g
\n" ); document.write( "x=100g\r
\n" ); document.write( "\n" ); document.write( "Therefore, there are 100 grams of salt already in the solution.\r
\n" ); document.write( "\n" ); document.write( "Now that we've determined x's value, we'll bring z into the equation. There are two ways to calculate z. z is equivalent to the sum of x and y. Remember, x is equal to 100 grams. So, z's equation is as follows:
\n" ); document.write( "z=100g+y\r
\n" ); document.write( "\n" ); document.write( "The other way to calculate z is as a percentage of the final solution. As the question states, we want the final solution to have a salt content of 40% (which we can write as .40). The final amount of solution can be written as below:
\n" ); document.write( "400g+y=total amount of solution after adding salt.
\n" ); document.write( "This is because we are adding y (the amount of salt needed to bring the salt content to 40 percent)to the amount of solution which we already have.
\n" ); document.write( "Therefore, the second way to express z is below:
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\n" ); document.write( "z=.40*(400g+y)\r
\n" ); document.write( "\n" ); document.write( "After we have two equations for z, we can set them equal to each other as follows:\r
\n" ); document.write( "\n" ); document.write( "100g+y=.40*(400g+y)\r
\n" ); document.write( "\n" ); document.write( "We then can distribute the .40 over the parenthesis.\r
\n" ); document.write( "\n" ); document.write( "100g+y=160g+.40y\r
\n" ); document.write( "\n" ); document.write( "And then we can subtract 100 grams from both sides of the equation.
\n" ); document.write( "y=60g+.40y\r
\n" ); document.write( "\n" ); document.write( "Next, we subtract .40 y from both sides of the equation to get y on one side.
\n" ); document.write( ".6y=60g\r
\n" ); document.write( "\n" ); document.write( "Finally, we can divide both sides by .6 to isolate y.
\n" ); document.write( "y=100g\r
\n" ); document.write( "\n" ); document.write( "Therefore, you must add 100g of salt to the solution to make it 40 percent salt.
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