document.write( "Question 386269: Find the equation of a line passing through the point (- 2, - 4) and parallel to the line 2x + 3y = 24. \n" ); document.write( "
Algebra.Com's Answer #273085 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
Find the equation of a line passing through the point (- 2, - 4) and parallel to the line 2x + 3y = 24.
\n" ); document.write( "....
\n" ); document.write( "(- 2, - 4) and parallel to the line
\n" ); document.write( "2x + 3y = 24
\n" ); document.write( "3y=-2x+24
\n" ); document.write( "/3
\n" ); document.write( "y=(-2x/3)+8
\n" ); document.write( "...
\n" ); document.write( "slope m = (-2/3)
\n" ); document.write( "...
\n" ); document.write( "Parallel line will have same slope = (-2/3)
\n" ); document.write( "find b
\n" ); document.write( "y= mx+b
\n" ); document.write( "(-2,-4) m=(-2/3)
\n" ); document.write( "plug these values
\n" ); document.write( "-4=(-2/3)*-2 +b
\n" ); document.write( "-4=4/3+b
\n" ); document.write( "b=-4-4/3
\n" ); document.write( "b=(-16/3)
\n" ); document.write( "...
\n" ); document.write( "equation is
\n" ); document.write( "y=(-2/3)x-16/3
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( "
\n" );