document.write( "Question 385955: Good Morning:
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document.write( "I am still working with back substitution to solve the system of linear equations. Can you help me? \r
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document.write( "{3/4x+2y+2/3z=-3
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document.write( "{-4/5y-4/3z=1
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document.write( "{z=3\r
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document.write( "Thanks so much! \r
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document.write( "Denise \n" );
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Algebra.Com's Answer #273058 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( "z = 3 \n" ); document.write( ": \n" ); document.write( "Replace z with 3 in the 1st two equations \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Fortunately, this will cause two of fractions to cancel out \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Multiply the above equation by -5, get rid of the denominator change the signs, results: \n" ); document.write( "4y = -5(5) \n" ); document.write( "y = \n" ); document.write( "y = -6.25 \n" ); document.write( ": \n" ); document.write( "Find x, substitute for y and z \n" ); document.write( " \n" ); document.write( "y=-6.25, z=3 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Multiply by 4 \n" ); document.write( "3x = 4(7.5) \n" ); document.write( "3x = 30 \n" ); document.write( "x = 10 \n" ); document.write( ": \n" ); document.write( "Summarize: x=10; y=-6.25, z=3\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |