document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=386195>Question 386195</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am having toruble with substitution. I dont understand how to find the solution. A problem I am stuck on is y= 8x-5 y=2x+1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #273033 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=273033\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> substitute the EQUIVALENT value for y from one equation into the other equation<BR>\n" );
document.write( "this should leave an equation with only x in it\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "in the 1st equation , y equals (8x-5) ; (8x-5) is the equivalent value\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "substituting into the 2nd equation ___ (8x-5) = 2x+1\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "solving for x ___ 6x = 6 ___ x = 1\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "substituting back to find y ___ y = 8(1) - 5 ___ y = 3\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );