document.write( "Question 386132: Graph the equation \r
\n" ); document.write( "\n" ); document.write( "2x^2 + 2y^2 -16x + 4y - 38 = 0
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Algebra.Com's Answer #273015 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "First, what is it? 2nd degree equation in two variables. Has to be a conic section.\r
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\n" ); document.write( "\n" ); document.write( "Has both and terms -- NOT a parabola.\r
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\n" ); document.write( "\n" ); document.write( " and terms have the same sign -- NOT a hyperbola.\r
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\n" ); document.write( "\n" ); document.write( "The coefficients on the and terms are equal -- NOT an ellipse.\r
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\n" ); document.write( "\n" ); document.write( "Has to be a circle.\r
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\n" ); document.write( "\n" ); document.write( "Find the center and radius. Complete the square on each of the two variables.\r
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\n" ); document.write( "\n" ); document.write( "Move the constant term into the RHS:\r
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\n" ); document.write( "\n" ); document.write( "Group same type variables:\r
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\n" ); document.write( "\n" ); document.write( "Divide by the lead coefficient:\r
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\n" ); document.write( "\n" ); document.write( "Divide the coefficient on th 1st degree x term by 2, square the result, add that result to both sides.\r
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\n" ); document.write( "\n" ); document.write( "Repeat for the coefficient on the 1st degree y term:\r
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\n" ); document.write( "\n" ); document.write( "Factor the two perfect square trinomials in the LHS and simplify the RHS:\r
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\n" ); document.write( "\n" ); document.write( "Hence you have a circle centered at (4,-1) with radius 6.\r
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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