document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=386060>Question 386060</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangular frame is 12 inches more than twice the width. The area inside the frame is 1040 square inches. Find the dimension of the frame.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #273001 by </B><A HREF=/tutors/aboutme.mpl?userid=JimboP1977><B>JimboP1977(311)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JimboP1977><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JimboP1977><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=273001\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Length = L<BR>\n" );
document.write( "Width = W\r<BR>\n" );
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document.write( "L+12 = 2W<BR>\n" );
document.write( "L x W = 1040<BR>\n" );
document.write( "(2W-12) x W = 1040<BR>\n" );
document.write( "2W^2 -12W = 1040\r<BR>\n" );
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document.write( "W^2 - 6W = 520\r<BR>\n" );
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document.write( "(W-3)^2 - 9 = 520\r<BR>\n" );
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document.write( "W = 529^(1/2) + 3\r<BR>\n" );
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document.write( "W = 26\r<BR>\n" );
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document.write( "L = 40\r<BR>\n" );
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