document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=42164>Question 42164</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write the equation of the line with given slope and y-intercept.  Then graph each the line using the slope and y-intercept. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #27299 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=27299\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Of course you did not supply the specific slope and y-intercept, but if you had, this is what you would do...<BR>\n" );
document.write( "Given m = 2/3 and y-int = -4<BR>\n" );
document.write( "you plug into the slope-intercept form<BR>\n" );
document.write( "y = mx + b<BR>\n" );
document.write( "where 2/3 goes in for m and -4 goes in for b...giving you<BR>\n" );
document.write( "y = (2/3)x - 4<BR>\n" );
document.write( "To graph it, put a point on the y-axis at -4...the actual point is (0, -4)...from there, then, go up two and to the right three (a slope of 2/3) and put another point...then connect 'em and you're done... </SPAN>\n" );
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