document.write( "Question 386077: a chemist needs 120 milliliters of a 50% solution but has only 48% and 60% solutions available. Find how many milliliters of each that should be mixed to get the desired solution. \n" ); document.write( "
Algebra.Com's Answer #272980 by stanbon(75887)\"\" \"About 
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a chemist needs 120 milliliters of a 50% solution but has only 48% and 60% solutions available. Find how many milliliters of each that should be mixed to get the desired solution.
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\n" ); document.write( "Equations:
\n" ); document.write( "Quantity: x + y = 120 ml
\n" ); document.write( "Active::: 0.48x + 0.60y = 0.50*120
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\n" ); document.write( "Multiply thru 1st by 48
\n" ); document.write( "Multiply thru 2nd by 100
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\n" ); document.write( "48x + 48y = 48*120
\n" ); document.write( "48x + 60y = 50*120
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\n" ); document.write( "12y = 2*120
\n" ); document.write( "y = 20 ml (amt. of 60% solution needed in the mix)
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\n" ); document.write( "Since x + y = 120 , x = 100 ml (amt. of 48% solution needed in the mix)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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