document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=41980>Question 41980</A>: <I><SPAN STYLE=\"word-break: break-all;\"> sin-1(-(the square root of 3)/2)<BR>\n" );
document.write( "aka the angle whose sine is the (negative (square root of 3) divided by 2)\r<BR>\n" );
document.write( "\n" );
document.write( "the possible answers are A. -30 degrees B. -60 degrees C. 150 degrees D. 120 degrees </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #27298 by </B><A HREF=/tutors/aboutme.mpl?userid=abcdefg><B>abcdefg(37)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=abcdefg><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=27298\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sin-1(-(the square root of 3)/2)<BR>\n" );
document.write( "aka the angle whose sine is the (negative (square root of 3) divided by 2)\r<BR>\n" );
document.write( "\n" );
document.write( "the possible answers are A. -30 degrees B. -60 degrees C. 150 degrees D. 120 degrees<BR>\n" );
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document.write( "sin-1=-sqrt3/2<BR>\n" );
document.write( "(-sqrt3 is -1.732)<BR>\n" );
document.write( "-1.732/2= -0.866<BR>\n" );
document.write( "look up sin -0.866 <BR>\n" );
document.write( "sin -0.866 is -60 degrees<BR>\n" );
document.write( "answer is -60 degrees<BR>\n" );
document.write( "answer B </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );