document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=41979>Question 41979</A>: <I><SPAN STYLE=\"word-break: break-all;\"> tan-1 (– the square root of 3)<BR>\n" );
document.write( "aka- the angle whose tangent is the negative square root of three\r<BR>\n" );
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document.write( "the possible answers are A. -30 degrees   B. -60 degrees   C. 150 degrees   D.  120 degrees </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #27297 by </B><A HREF=/tutors/aboutme.mpl?userid=abcdefg><B>abcdefg(37)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=abcdefg><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=27297\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> aka- the angle whose tangent is the negative square root of three<BR>\n" );
document.write( "tan-1=-sqrt3<BR>\n" );
document.write( "sqrt3 is -1.732 so...\r<BR>\n" );
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document.write( "look up tan 1.732<BR>\n" );
document.write( "tan 1.732= 60<BR>\n" );
document.write( "-60  <----answer\r<BR>\n" );
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document.write( "(cuz it was negative to start)\r<BR>\n" );
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document.write( " </SPAN>\n" );
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