document.write( "Question 385999: What is perpendicular to the graph of 2x - 3y = 12 passing through the poin (4,3) \n" ); document.write( "
Algebra.Com's Answer #272960 by nerdybill(7384)\"\" \"About 
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What is perpendicular to the graph of 2x - 3y = 12 passing through the poin (4,3)
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\n" ); document.write( "First, determine slope of:
\n" ); document.write( "2x - 3y = 12
\n" ); document.write( "-3y = -2x + 12
\n" ); document.write( "y = (2/3)x - 4
\n" ); document.write( "slope then is 2/3
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\n" ); document.write( "A line that is perpendicular must have a \"negative reciprocal\" slope:
\n" ); document.write( "(2/3)m = -1
\n" ); document.write( "m = -3/2 (new line slope)
\n" ); document.write( "along with given point of (4,3) -- plug it into \"point-slope\" form:
\n" ); document.write( "y - y1 = m(x - x1)
\n" ); document.write( "y - 3 = (-3/2)(x - 4)
\n" ); document.write( "y - 3 = (-3/2)x + 6
\n" ); document.write( "y = (-3/2)x + 9 (this is what they're looking for)\r
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