document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=385954>Question 385954</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello! I am trying to solve this one using back substitution.  <BR>\n" );
document.write( "{x-y-2z=10<BR>\n" );
document.write( "{2y+2z=-8<BR>\n" );
document.write( "z=-1\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #272952 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=272952\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Linear-systems/385954 (2010-12-14 08:47:52): Hello! I am trying to solve this one using back substitution. <BR>\n" );
document.write( "x-y-2z=10<BR>\n" );
document.write( "2y+2z=-8<BR>\n" );
document.write( "z=-1 <BR>\n" );
document.write( "------------<BR>\n" );
document.write( "2y+2z=-8<BR>\n" );
document.write( "Sub for z<BR>\n" );
document.write( "2y + 2*-1 = -8<BR>\n" );
document.write( "2y = -6<BR>\n" );
document.write( "y = -3<BR>\n" );
document.write( "-------<BR>\n" );
document.write( "x-y-2z=10<BR>\n" );
document.write( "Sub for y & z<BR>\n" );
document.write( "x - (-3) -2(-1) = 10<BR>\n" );
document.write( "x + 3 + 2 = 10<BR>\n" );
document.write( "x = 5<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );