document.write( "Question 385914: a man is four timesaas old as his son. in 3 years, the father will be three times as old as his son. how old is each now? \n" ); document.write( "
Algebra.Com's Answer #272921 by mananth(16946)![]() ![]() You can put this solution on YOUR website! son = x years \n" ); document.write( "man = 4x \n" ); document.write( ".. \n" ); document.write( "ages after 3 years \n" ); document.write( "son x+3 \n" ); document.write( "man=4x+3 \n" ); document.write( "... \n" ); document.write( "4x+3=3(x+3) \n" ); document.write( "4x+3=3x+9 \n" ); document.write( "4x-3x=9-3 \n" ); document.write( "x=6 son's age \n" ); document.write( "Mans age = 4*6 = 24 years \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |