document.write( "Question 385911: log2x=4 \n" ); document.write( "
Algebra.Com's Answer #272914 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
log2x=4
\n" ); document.write( "...
\n" ); document.write( "log 2x = 4\r
\n" ); document.write( "\n" ); document.write( "10^(log 2x) = 10^(4)\r
\n" ); document.write( "\n" ); document.write( "by applying 10^ to each side you dissolve the log\r
\n" ); document.write( "\n" ); document.write( "becomes 2x = 10^(4)\r
\n" ); document.write( "\n" ); document.write( "x = (1/2)*10^(4)\r
\n" ); document.write( "\n" ); document.write( "x =5000\r
\n" ); document.write( "\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( "
\n" );