document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=385899>Question 385899</A>: <I><SPAN STYLE=\"word-break: break-all;\">  Pure Acid is to be added to a 10% acid solution to obtain 27 litters of 20% acid solution. What amounts of each should be used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #272913 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=272913\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = # liters of pure acid that had to be added.  Then<BR>\n" );
document.write( "Then x + 0.10(27- x) = 0.20*27;<BR>\n" );
document.write( "x + 2.7 - 0.10x = 5.4;<BR>\n" );
document.write( "0.90x = 2.7;<BR>\n" );
document.write( "x = 3 liters of pure acid. </SPAN>\n" );
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