document.write( "Question 385897: write an equation in the form ax^2+bx+c=0 given one root of 5+i \n" ); document.write( "
Algebra.Com's Answer #272909 by robertb(5830)\"\" \"About 
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Divide both sides by a: \"x%5E2+%2B+bx%2Fa+%2B+c%2Fa+=+0\". If one root is 5+i then 5 - i is also a root. Then \"-b%2Fa+=+5%2Bi+%2B+5+-+i+=+10\", or b = -10a. Also, \"c%2Fa+=+%285%2Bi%29%285+-+i%29+=+25+-i%5E2+=+26\", or c = 26a. Therefore \"ax%5E2%2Bbx%2Bc=ax%5E2+-+10ax+%2B+26a+=+0\", or \"x%5E2+-+10x+%2B+26+=+0\", after dividing by a. \n" ); document.write( "
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