document.write( "Question 385787: how many pounds of 40 cent nuts and how many pounds of 25 cent nuts must you a dealer use to produce a misture of 90 pounds to sell at 31 cents per pound? \n" ); document.write( "
Algebra.Com's Answer #272878 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! how many pounds of 40 cent nuts and how many pounds of 25 cent nuts must you a dealer use to produce a misture of 90 pounds to sell at 31 cents per pound? \n" ); document.write( "--------- \n" ); document.write( "Equations: \n" ); document.write( "Quantity: x + y = 90 lbs \n" ); document.write( "Value:::40x + 25y = 31*90 cents \n" ); document.write( "---------------------------------- \n" ); document.write( "Multiply Quantity by 40 \n" ); document.write( "---- \n" ); document.write( "40x + 40y = 40*90 \n" ); document.write( "--- \n" ); document.write( "Subtract from Value and solve for \"y\": \n" ); document.write( "-15y = -9*90 \n" ); document.write( "y = 54 lbs (amt. of 25 cent nuts needed in the mixture) \n" ); document.write( "--- \n" ); document.write( "Since x+y = 90, x = 36 lbs (amt. of 40 cent nuts needed in the mixture) \n" ); document.write( "------ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |