document.write( "Question 385787: how many pounds of 40 cent nuts and how many pounds of 25 cent nuts must you a dealer use to produce a misture of 90 pounds to sell at 31 cents per pound? \n" ); document.write( "
Algebra.Com's Answer #272878 by stanbon(75887)\"\" \"About 
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how many pounds of 40 cent nuts and how many pounds of 25 cent nuts must you a dealer use to produce a misture of 90 pounds to sell at 31 cents per pound?
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\n" ); document.write( "Equations:
\n" ); document.write( "Quantity: x + y = 90 lbs
\n" ); document.write( "Value:::40x + 25y = 31*90 cents
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\n" ); document.write( "Multiply Quantity by 40
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\n" ); document.write( "40x + 40y = 40*90
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\n" ); document.write( "Subtract from Value and solve for \"y\":
\n" ); document.write( "-15y = -9*90
\n" ); document.write( "y = 54 lbs (amt. of 25 cent nuts needed in the mixture)
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\n" ); document.write( "Since x+y = 90, x = 36 lbs (amt. of 40 cent nuts needed in the mixture)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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