document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=385741>Question 385741</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Equation of a circle if I have P (-5,2) and Q (3,-8) I have it figured as -1, -3<BR>\n" );
document.write( "then r= square root of (-1-3)^2 + (-3+8)^2 = sqaure root 41 so the equation of the circle would be (x+1)^2 + (y+3)^2 = 41.\r<BR>\n" );
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document.write( "But thing seems a miss.... could you look this over for me? Thanks\r<BR>\n" );
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document.write( "Melody </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #272851 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=272851\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You're saying that (-1,-3) is the center of the circle.  Are the points P and Q given as the endpoints of a diameter?  Incidentally if (-1,-3) is indeed the center of the circle then 41 is the square of the radius... </SPAN>\n" );
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