document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=385638>Question 385638</A>: <I><SPAN STYLE=\"word-break: break-all;\"> This is a percents system of equations word problem. Please help me solve it.\r<BR>\n" );
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document.write( "A chemistry student needs 40 milliliters (mL) of a 14% acid solution. She had two acid solutions, A and B, to mix together to form the 40 mL acid solution. Acid solution A is 10% and acid solution B is 20% acid. How much of each solution should be used?\r<BR>\n" );
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document.write( "I have created one equation: x + y = 40\r<BR>\n" );
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document.write( "The second equation I have written is not finished: <BR>\n" );
document.write( ".1x + .2y = ????\r<BR>\n" );
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document.write( "How do I finish the second equation? And why? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #272848 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=272848\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A chemistry student needs 40 milliliters (mL) of a 14% acid solution.<BR>\n" );
document.write( " She had two acid solutions, A and B, to mix together to form the 40 mL acid solution.<BR>\n" );
document.write( "Acid solution A is 10% and acid solution B is 20% acid.<BR>\n" );
document.write( " How much of each solution should be used?<BR>\n" );
document.write( "I have created one equation: x + y = 40<BR>\n" );
document.write( "The second equation I have written is not finished:<BR>\n" );
document.write( "It should be:<BR>\n" );
document.write( ".1x + .2y = .14(40)<BR>\n" );
document.write( ".1x + .2y = 5.6<BR>\n" );
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document.write( "Using the first equation<BR>\n" );
document.write( "x + y = 40<BR>\n" );
document.write( "x = (40-y)<BR>\n" );
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document.write( "In the 2nd equation, replace x with (40-y)<BR>\n" );
document.write( ".1(40-y) + .2y = 5.6<BR>\n" );
document.write( "4 - .1y + .2y = 5.6<BR>\n" );
document.write( ".1y = 5.6 - 4<BR>\n" );
document.write( ".1y = 1.6<BR>\n" );
document.write( "y = 16 liters of 20% solution<BR>\n" );
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document.write( "I'm sure you can find x. </SPAN>\n" );
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